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| Numberacy problem https://warwickshireonline.com/viewtopic.php?f=2&t=1323 |
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| Author: | optrex [ Tue Oct 17, 2006 8:19 am ] |
| Post subject: | Numberacy problem |
Using the numbers 1 5 6 and 7 make 21 You must use all the numbers. Anyone got an idea? |
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| Author: | Shizara [ Tue Oct 17, 2006 10:05 am ] |
| Post subject: | |
I don't see anything about not using any number more than once. The only proviso is using all the numbers... Sooo... The sum of 1 + 5 + 6 +7 = 19 Adding the number 1 twice more would = 21 |
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| Author: | optrex [ Tue Oct 17, 2006 10:22 am ] |
| Post subject: | |
you can only use them once. The closest I have is 22 by a number of routes unless I use 5+7=12 12 divide 6=2, then "add" the 1 to make 21 |
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| Author: | Shizara [ Tue Oct 17, 2006 10:29 am ] |
| Post subject: | |
Though I daresay there is a more complex way involving multiplying 6 x 7 = 42 Then, 5 - 1 = 4. This is where my brain hurts as I cope with basic numbers hence the simplistic calculation above... I suspect the next thing will be something about roots that are not round and buried in the ground but are in fact square, which, like the simplistic calculation of 1 + 1, likely will equal 2. Sooo... 42 divided by 2 would = 21. I think the first calculation was easier! |
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